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← 算法资料库/Math/Euclidean Algorithm
算法阅读笔记

Euclidean Algorithm

Euclid's algorithm finds gcd(a, b) by repeatedly replacing (a, b) with (b, a mod b) until the remainder becomes zero.

类型算法分类Math深度初级典型复杂度O(log min(a,b))
简短面试回答

先从这个心智模型开始

Euclid's algorithm finds gcd(a, b) by repeatedly replacing (a, b) with (b, a mod b) until the remainder becomes zero.

01
简单解释

它如何工作,不堆砌不必要的术语

01

The key property is gcd(a, b) = gcd(b, a mod b).

02

It is much faster than checking every possible divisor.

02
执行过程

把算法读成一连串决策

01

State the mathematical identity/property.

02

Choose numeric representation and constraints.

03

Translate the property into an iterative/recursive computation and analyze precision.

记住一个小例子

Read a tiny input by hand and write down the state after every important operation. For Euclidean Algorithm, the goal is to make the invariant visible rather than to memorize code.

易读的 JavaScript 实现JavaScript
function gcd(a, b) {
  a = Math.abs(a);
  b = Math.abs(b);
  while (b !== 0) {
    [a, b] = [b, a % b];
  }
  return a;
}
如何阅读这段代码

不要死记语法。跟踪每一行中发生变化的状态,并把它与上面描述的不变量联系起来。

复杂度

O(log min(a,b))

Do not quote this complexity mechanically. Ask which operation or input dimension it describes, then derive the cost from the loops, recursion depth, data-structure operations and any preprocessing assumptions.

03
何时使用

适用场景

  • Use the direct mathematical property when it removes unnecessary brute force.
04
常见错误

通常哪里会出错

  • Ignoring floating-point precision or integer range.
  • Using a formula outside its valid assumptions.
面试中如何解释

专业回答结构

Explain the invariant/property behind the modulo step; do not present it as a magic loop.

问题→核心思路→不变量 / 状态→Big-O→权衡
快速面试检查

What problem does Euclidean Algorithm solve?

Euclid's algorithm finds gcd(a, b) by repeatedly replacing (a, b) with (b, a mod b) until the remainder becomes zero.

关于复杂度应该提到什么?

Its typical cost here is O(log min(a,b)), but a complete answer should connect that cost to the representation, input constraints and the dominant operations.

最常见的错误是什么?

Ignoring floating-point precision or integer range.

继续阅读Number theoryNumerical precisionRecurrences
来源与延伸阅读

本课程为安静学习和面试准备独立编写,主题目录参考 trekhleb/javascript-algorithms。上游仓库包含原始实现、测试以及每个主题的 README 参考资料。

打开上游仓库 ↗
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